National Institute of Technology Master of Computer Applications Common Entrance Test
Hi,
Dear Aspirant
Here is the list of NITs and their cut off ranks of NIMCET for OBC category-:
Hope this helps.
Thankyou
Dear candidate, though it's much late but here's the elegibilty criteria for the exam:
https://it.careers360.com/articles/nimcet-eligibility-criteria
The basic NIMCET eligibility criteria requires Indian candidates to be graduates in S cience/ IT/ CA/ Technology or Engineering, with at least 60% marks or 6.5 CGPA. Only eligible candidates will be able to apply
It is always good to have a plan B incase plan A does not work. However the competitive exam for both the courses which you want to pursue are pretty difficult. You can definitely prepare for both if you have the capacity to undertake both preparation at the same
HI...
CAT is tougher than NIMCET. But you can prepare for both the exams.
English and Mathematics is almost of the same level in both. But Logical Reasoning and Data Interpretation much harder in CAT than in NIMCET. There are also 10 questions of Computer Awareness.
One major difference between
Dear aspirant, for NIMCET the notifications ans the online applications are expected to be released in the first week of March 2020. The last date to fill the form would be in the last week of March 2020.The admits cards are released in the second week of may and the
Hello Rahul
Yes, you can!! you may have to qualify entrance exam but there are a few college which give direct admission to students.Colleges prefer students those who have studied Mathematics at 10+2 level or graduation . As you have studied Maths and computer at graduation and have marks between
Hey Kajal! Different National Institute of Technology have different fees structure but for reference i have mentioned National Institute of Technology Rourkela - Fees for MCA course so you can get an idea.
Fee Amount for MCA
Hello Shalini,
Aggregate = { MARKS OBTAINED ×100}/Total Marks .
Step 1 :- Add up marks of all your subjects
Step 2:- Divide the total by no. of subjects of which u had added up the marks
Simple logic is : Total number of marks obtained divided by number of
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